How to sort the letters in a string alphabetically in Python


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Is there an easy way to sort the letters in a string alphabetically in Python?

So for:

a = 'ZENOVW'

I would like to return:

'ENOVWZ'


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    You can do:

    >>> a = 'ZENOVW'
    >>> ''.join(sorted(a))
    'ENOVWZ'
    

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    >>> a = 'ZENOVW'
    >>> b = sorted(a)
    >>> print b
    ['E', 'N', 'O', 'V', 'W', 'Z']
    

    sorted returns a list, so you can make it a string again using join:

    >>> c = ''.join(b)
    

    which joins the items of b together with an empty string '' in between each item.

    >>> print c
    'ENOVWZ'
    

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    Sorted() solution can give you some unexpected results with other strings.

    List of other solutions:

    Sort letters and make them distinct:

    >>> s = "Bubble Bobble"
    >>> ''.join(sorted(set(s.lower())))
    ' belou'
    

    Sort letters and make them distinct while keeping caps:

    >>> s = "Bubble Bobble"
    >>> ''.join(sorted(set(s)))
    ' Bbelou'
    

    Sort letters and keep duplicates:

    >>> s = "Bubble Bobble"
    >>> ''.join(sorted(s))
    ' BBbbbbeellou'
    

    If you want to get rid of the space in the result, add strip() function in any of those mentioned cases:

    >>> s = "Bubble Bobble"
    >>> ''.join(sorted(set(s.lower()))).strip()
    'belou'
    

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    You can use reduce

    >>> a = 'ZENOVW'
    >>> reduce(lambda x,y: x+y, sorted(a))
    'ENOVWZ'
    

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    Python functionsorted returns ASCII based result for string.

    INCORRECT: In the example below, e and d is behind H and W due it's to ASCII value.

    >>>a = "Hello World!"
    >>>"".join(sorted(a))
    ' !!HWdellloor'
    

    CORRECT: In order to write the sorted string without changing the case of letter. Use the code:

    >>> a = "Hello World!"
    >>> "".join(sorted(a,key=lambda x:x.lower()))
    ' !deHllloorW'
    

    If you want to remove all punctuation and numbers. Use the code:

    >>> a = "Hello World!"
    >>> "".join(filter(lambda x:x.isalpha(), sorted(a,key=lambda x:x.lower())))
    'deHllloorW'
    

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    the code can be used to sort string in alphabetical order without using any inbuilt function of python

    k = input("Enter any string again ")

    li = []
    x = len(k)
    for i in range (0,x):
        li.append(k[i])
    
    print("List is : ",li)
    
    
    for i in range(0,x):
        for j in range(0,x):
            if li[i]<li[j]:
                temp = li[i]
                li[i]=li[j]
                li[j]=temp
    j=""
    
    for i in range(0,x):
        j = j+li[i]
    
    print("After sorting String is : ",j)
    

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    Really liked the answer with the reduce() function. Here's another way to sort the string using accumulate().

    from itertools import accumulate
    s = 'mississippi'
    print(tuple(accumulate(sorted(s)))[-1])
    

    sorted(s) -> ['i', 'i', 'i', 'i', 'm', 'p', 'p', 's', 's', 's', 's']

    tuple(accumulate(sorted(s)) -> ('i', 'ii', 'iii', 'iiii', 'iiiim', 'iiiimp', 'iiiimpp', 'iiiimpps', 'iiiimppss', 'iiiimppsss', 'iiiimppssss')

    We are selecting the last index (-1) of the tuple